B^2+10b+25=4

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Solution for B^2+10b+25=4 equation: 



^2+10B+25=4

We move all terms to the left:

^2+10B+25-(4)=0

determiningTheFunctionDomain
10B+25-4+^2=0

We add all the numbers together, and all the variables

10B=0

B=0/10

B=0

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